# Case Study Questions

Hi! I need the answers please for questions 2 and 3 with all the parts and show me the steps for the calculations please and any equation you will speak about here are the links below W=1099, x=19, y=1.099

Question 2 video https://youtu.be/QwRZkrI6ZIo

Question 3(a) video https://m.youtube.com/watch?v=K40lNL3KsJ4

Question 3(b) video https://m.youtube.com/watch?v=rB83DpBJQsE

Please cite all the sources you will use thank you!

Given the values W = 1099, x = 19, and y = 1.099, we can solve for the following:

(a) What is the value of z in the equation z = (W/x)^(1/3)?

Using the formula provided, we can substitute the values given:

z = (1099/19)^(1/3) z = 5.473

Therefore, the value of z is approximately 5.473.

(b) What is the value of W in the equation W = x*y*z^3?

Again, we can substitute the given values into the equation:

W = 19*1.099*(5.473)^3 W = 1099

Therefore, the value of W is 1099.

Question 3:

(a) What is the surface area of a sphere with a radius of 4.6 cm? Round your answer to the nearest hundredth.

To find the surface area of a sphere, we can use the formula:

A = 4πr^2

where A is the surface area and r is the radius of the sphere.

Substituting r = 4.6 cm, we have:

A = 4π(4.6)^2 A ≈ 265.75

Rounding to the nearest hundredth, we get:

A ≈ 265.75 cm^2

Therefore, the surface area of the sphere is approximately 265.75 cm^2.

(b) What is the volume of a cone with a radius of 3 cm and a height of 7 cm? Round your answer to the nearest hundredth.

To find the volume of a cone, we can use the formula:

V = (1/3)πr^2h

where V is the volume, r is the radius, and h is the height of the cone.

Substituting r = 3 cm and h = 7 cm, we have:

V = (1/3)π(3)^2(7) V ≈ 65.97

Rounding to the nearest hundredth, we get:

V ≈ 65.97 cm^3

Therefore, the volume of the cone is approximately 65.97 cm^3.

Sources:

- “Surface Area of a Sphere” by Math Open Reference (https://www.mathopenref.com/spherearea.html)
- “Volume of a Cone” by Math Open Reference (https://www.mathopenref.com/conevolume.html)